Which quantity is equivalent to 39 grams of lif?

This question is incomplete, the completed question is below.

(a) 1.0 mole  

(b) 2.0 mole  

(c) 0.50 mole

(d) 1.5 mole

The correct option is d

Explanation:

LiF is Lithium flouride. Lithium (Li) has a molar mass of 7 g/mol while flourine (F) has a molar mass of 19 g/mol. Hence, 1 mole of LiF will be

7 + 19 = 26 g/mol

If 1 mole of LiF = 26g,

X mole of LiF = 39g

When you cross multiply, you will have

X mole x 26g = 1 mole x 39g

make X the subject and you will have

X mole = 1 mole x 39g/26g

X mole = 1.5 mole

Hence, 1.5 mole of LiF is equivalent to 39 grams of LiF

the maximum mass of nh3 is nh3 in grams

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.