A0.1964-g sample of quinone (c6h4o2) is burned in a bomb calorimeter that has a heat capacity of 1.56 kj/c. the temperature of the calorimeter increases by 3.2c. calculate the energy of combustion of quinone per gram and per mole

Quinone mass in grams = 0.1964g 
Heat capacity = 1.56 KJ/C 
Temerature = 3.2C 
Heat energy that is lost while combustion, dH = heat capacity x temp  
dH = 1.56 KJ/c x 3.2c => dH = 4.992 KJ 
Since it is the energy lost, it is represented as dH = -4.992 KJ 
Calculating the heat energy per gram = 4.992/0.1964 = -25.4 KJ/m 
Molar weight of the compound is 108.1 g/mol 
Calculating the heat energy per mole = -25.4 KJ/g x 108.1 g/mol => -25.4 x
108.1 KJ/mol 
Heat energy per mole = -2747.63 KJ/mol

It shows that the experiment is designed properly.