If one mole (1.00 mol) of copper (cu) has 6.02x10^23 atoms of copper, how many molecules are in 1.00 mol of nitrogen gas (n2) a.1.204 x 10^24 b.12.04 x 10^23 c.6.02 x 10^23 d.3.01 x 10^23 e.3.01 x 10^22

Answer is: c. 6.02 x 10^23.

n(N₂) = 1.00 mol; amount of nitrogen molecules.

Na = 6.02·10²³ 1/mol.

Na is Avogadro number or Avogadro constant (the number of particles, in this example nitrogen molecules, that are contained in the amount of substance given by one mole).

N(N₂) = n(N₂) · Na.

N(N₂) = 1.00 mol · 6.02·10²³ 1/mol.

N(N₂) = 6.02·10²³; number of nitrogen molecules.

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