Propane, c3h8, burns to produce carbon dioxide and water by the equation below. what is the coefficient in front of the carbon dioxide in the balanced equation? c3h8 + o2 \rightarrow→→ co2 + h2o

for left side: 3 c, 8 h, 2 o. for right side, 1 c, 3 o, 2 hwe want to balance oxygen last because it is the only one that is isolated. we can fine tune it at the end.put a coefficient on right side to balance the number of carbons.now make the number of hydrogens eventhere are 8 h on the left and 2 h on the right. put a coefficient on the right side like so: now we have 10 oxygens on the right and 2 on the left. to get the left side to have 10 oxygens, put a coefficient of 5 (5 * 2 = 10)the coefficient in front of  in the balanced equation is 3.

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.