Calculate the quantity of energy required to change 8.22 mol of liquid water to steam at 100oc. the molar heat of vaporization of water is 40.6 kj/mol.

Since  the water  is  at  100 degrees  then   it take  40.6 kj/mol   to  change 1  mole of  water at 100 degrees into  steam at  100  degrees
  the  moles  of water  8.22mol
since  one  mole  take 40.6kj/mol   8.22mol  will  be  =
8.22mol  x  40.6 kj/mol =333.732  kj
 

30litre of li2o is 1.0002mole approximately 1 mole