The serum potassium level of a client who has diabetic ketoacidosis is 5.4 meq/l (5.4 mmol/l). what would the nurse expect to see on the ecg tracing monitor?

Potassium is the primary intracellular cation (that is positively charged ion), and amid ketoacidosis as it moves out of cells into the extracellular compartment to supplant potassium lost because of glucose-incited osmotic diuresis; overstimulation of the cardiovascular muscle comes about. The T wave is discouraged in hypokalemia. At first, the QT fragment is short, and as the potassium level ascents, the QRS complex augments. P waves are irregular on the grounds that the PR interim might be drawn out and the P wave might be lost; nonetheless, the T wave is topped, not discouraged. The ST portion winds up noticeably discouraged. The PR interval or period is delayed, and the P wave might be lost. QRS edifices and along these lines T waves end up plainly unpredictable, and the rate does not really change.

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when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol