Answers: 1
Chemistry, 22.06.2019 06:30, angelrenee2000
Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol
Answers: 1
Chemistry, 22.06.2019 13:30, bryce99
In a ni-cd battery, a fully charged cell is composed of nickelic hydroxide. nickel is an element that has multiple oxidation states. assume the following proportions of the states: nickel charge proportions found 0 0.17 +2 0.3 +3 0.33 +4 0.5 (a) determine the mean of the nickel charge. enter the answer to 2 decimal places.(b) determine the cumulative distribution function of nickel charge.
Answers: 2
Chemistry, 22.06.2019 14:30, joejoefofana
Consider the reduction reactions and their equilibrium constants. cu+(aq)+eββ½βββcu(s)pb2+(aq)+2eββ½βββ pb(s)fe3+(aq)+3eββ½βββfe(=6.2Γ108=4. 0Γ10β5=9.3Γ10β3 cu + ( aq ) + e β β½ β β β cu ( s ) k =6.2Γ 10 8 pb 2 + ( aq ) +2 e β β½ β β β pb ( s ) k =4.0Γ 10 β 5 fe 3 + ( aq ) +3 e β β½ β β β fe ( s ) k =9.3Γ 10 β 3 arrange these ions from strongest to weakest oxidizing agent.
Answers: 3
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