How much energy does it take to convert .500 kg of ice at -20°c to steam at 250°c. specific heat capacities: ice: 2.03 j/g °c water: 4.2 j/g°c steam: 2.0 j/g c

Use the specific heat equation for each one:

Q = mCT

m is mass
T is change in temp
C is spec heat

You will not only have to calculate three different specific heats, but also do the heat of vaporization and heat of fusion.

Heat of vaporization is 3.33 * 10^5 J/Kg

Heat of Fusion is 2.26 * 10^6 J/Kg

You’ll want to make sure all your units match. So change all Kg to g (or g to Kg)

-20 to 0 = mC(Ice)T

Melt ice (fusion) = m(heat of fusion)

0 to 100 = mC(Water)T

Boil (Vaporization) = m(heat of vaporization)

100 to 250 = mC(Steam)T

Then add each one together