Chemistry, 24.07.2019 07:10, cathhgc95791

How much lead (ii) iodate, pb(io3)2 (molar mass = 557.0 g/mol), is precipitated when 3.20  102 ml of 0.285 m pb(no3)2(aq) are mixed with 386 ml of 0.512 m naio3(aq) solution? pb(no3)2(aq) + naio3(aq)  pb(io3)2(s) + nano3(aq)?

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How much lead (ii) iodate, pb(io3)2 (molar mass = 557.0 g/mol), is precipitated when 3.20  102 ml o...