28 ml of 0.10 m hcl is added to 60 ml of 0.10 m sr(oh)2. determine the concentration of oh− in the resulting solution.

0.52 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.10 M

Volume of solution = 28 mL = 0.028 L

Putting values in equation 1, we get:

Molarity of solution = 0.10 M

Volume of solution = 60 mL = 0.060 L

Putting values in equation 1, we get:

According to stoichiometry :

2 moles of neutralize 1 mole of

Thus 0.0028 moles of neutralize= of

Thus (0.006-0.0014) moles = 0.046 moles of  are left in 88 ml of solution.

Concentration of will be =

Thus the concentration of in the resulting solution is 0.52 M

the millers tale is the answer.