Determine the volume of 0.150 m naoh solution required to neutralize each sample of hydrochloric acid. the neutralization reaction is: naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) 25 ml of a 0.150 m hcl solution 55 ml of a 0.055 m hcl solution 175 ml of a 0.885 m hcl solution

The Volume of NaOH required to neutralize

1) 25 mL of a 0.150M HCl solution is 25 mL

2) 55 mL of a 0.055M HCl solution is 20.2 mL

3) 175 mL of 0.885M HCl solution is 1032.5 mL

Explanation: Neutralization reactions are defined as the reactions when an acid reacts with a base to form a salt and water.

For the reaction of HCl and NaOH,

To calculate the molarity of NaOH, we use the formula:

1.) 25 mL of a 0.150M of HCl solution.

Putting the values in above equation, we get

2.) 55 mL of a 0.055M of HCl solution.

Putting the values in above equation, we get

3.) 175 mL of a 0.885M of HCl solution.

Putting the values in above equation, we get

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons