Zn(s)+cu2+(aq)→zn2+(aq)+cu(s). part a under standard conditions, what is the maximum electrical work, in joules, that the cell can accomplish if 51.0 g of copper is plated out?

The energy in Joules is calculated as:

E = VQ

At standard conditions, the standard potential or the voltage is equal to 0.76 V. Next, we have to determine Q. The formula is as follows:

Q = nF, where n is the number of moles electron, while F is the Faraday's constant (96,500 C/mol e)

From the given reaction, notice that Zn was converted to Zn²⁺, while Cu²⁺ to Cu. So, 1 mol Cu = 2 mol e.

Q = 51 g Cu (1 mol Cu/63.55 g)(2 mol e/1 mol Cu)(96,500 C/mol e)
Q = 154885.92 C

Thus,
E = (0.76 V)(154885.92 C)
E = 117,713.3 J

The answer is !