Pentacarbonyliron(0) (fe(co)5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe(co)5+2pf3+h2→fe(co)2(pf3)2(h)2+3 co if 6.0 g of fe(co)5 reacts with 4.0 g of pf3 and 4.0 g of h2, which is the limiting reagent?

The limiting reactant can be determined by calculating the moles supplied / moles stoich ratio and the lowest is the limiting reactant.

Fe(CO)5 ratio = [6 g / 195.9 g/mol] / 1

Fe(CO)5 ratio = 0.0306

PF3 ratio = [4 g / 87.97 g/mol] / 2

PF3 ratio = 0.0227

H2 ratio = [4 g / 2 g/mol] / 1

H2 ratio = 2

We can see that PF3 has the lowest ratio, so it is the limiting reactant.

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.