Chemistry, 19.07.2019 18:50, ashleyrover11

What volume does 76 g of fluorine gas occupy at stp?

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answered: Retzzi

2 * 22.4 = 44.8 liters (if using pre 1982 standard) 2 * 22.7 = 45.4 liters (if using 1982 and later standard) First, let's determine how many moles of F2 we have. Atomic weight fluorine = 18.998403 Molar mass F2 = 2 * 18.998403 = 37.996806 g/mol Moles F2 = 76 g / 37.996806 g/mol = 2.000168119 mol Now we have a minor problem. What definition of STP are you using? Up until 1982, STP was defined as 0Â°C and 1 atmosphere (101.325 kPa) From 1982 and later, STP was defined as 0Â°C and 100 kPa Because of the difference in pressure between the two different definitions of STP, the molar volume of a gas is 22.414 liter/mol using the pre-1982 definition and 22.711 liter/mol using the 1982 and later definition. So you get to choose which of the following 2 answers. 2 * 22.4 = 44.8 liters (if using pre 1982 standard) 2 * 22.7 = 45.4 liters (if using 1982 and later standard) Unfortunately there's still a large number of text books in use using the standard that should have been obsolete 35 years ago.

answered: Guest

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

answered: Guest

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

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