The density of ice is 920 kg/m3 and that of sea water is 1030 kg/m3 . what fraction of the total volume of an iceberg is exposed? show your work, don't just state the answer.

To be floating, the gravity force of the iceberg should be same as the buoyancy force that result from the difference of the ice and water density.
The density of ice is 920 and water is 1030, then the difference should be: 1030kg/m3-920kg/m3= 110kg/m3

Let say that the volume of ice below the water is volume1 and the volume above the water(exposed volume) is volume2.
You can get this equation

volume1+volume2= 100%
volume1= 100%- volume2

Insert it into the buoyancy and gravity force will result
buoyancy=gravity
110kg/m3*volume1= 920kg/m3 *volume2
110kg/m3*(100%- volume2)= 920kg/m3 *volume2
110kg/m3 - 110kg/m3*volume2= 920kg/m3 *volume2
110kg/m3 = 1030kg/m3 *volume2
volume2= 110/1030= 0.1067= 10.7%

The product formed when bao and h2o  react together is                        ba(oh)2that is  bao + h2o = ba(oh)21 mole of    bao    react  1 mole of h2o  to    form  1 mole  of ba(oh)2

Answer:             1.0  × 10⁻⁵ msolution:                     as we know ph is given as,                                    ph  = -log [h⁺]and,                                    [h⁺]  =  10^-ph    (1)putting value of ph in eq. 1,                                    [h⁺]  =  10⁻⁵                                    [h⁺]  =  1.0  × 10⁻⁵ m