Chemistry, 19.07.2019 16:50, Jmarie08

How many moles of ions will be present in 716 ml of 0.450 m solution of sodium phosphate(aq)?

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Answers

answered: davis52202

Number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.

Solution:

$Na_3PO_4(aq)\rightarrow 3Na^+(aq)+PO_4^{3-}(aq)$

Volume of the solution 716 mL

Molarity of the solution : 0.450 M

$Molarity=\frac{\text{Number of moles}}{\text{Volume in Liters}}$

$0.450 mol/L=\frac{\text{Number of moles of }Na_3PO_4}{0.716 L}$

$\text{Number of moles of }Na_3PO_4=0.450mol/L\times 0.716=0.3222 moles$

According to reaction one mol Na_3PO_4 is giving 4 moles of ions.

Number of moles of ions in 0.716 L of 0.450 M solution is = $4\times 0.3222=1.2888 moles$

Hence,number of moles of ions in 0.716 L of 0.450 M solution is 1.2888 moles.

answered: Guest

1.consider the following balanced equation and answer parts a through. show calculations for each part.

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.

explanation:

answered: Guest

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.