What is the total number of p electrons in a single phosphorus atom in its ground state?

9 p-electrons

Explanation:

Phosphorus is a reactive chemical element that belongs to the group 15 and period 3 of the periodic table. It is a p-block element having atomic number 15.

The electronic configuration of phosphorus in the ground state is 1s² 2s² 2p⁶ 3s² 3p³.

Since, 6 electrons are present in the 2p subshell and 3 electrons are present in the 3p subshell.

Therefore, there are total 9 p-electrons in a phosphorus atom present in its ground state.

your parents i think this could be it

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%