A3.0-l sample of helium was placed in a container fitted with a porous membrane. half of the helium effused through the membrane in 24 hours. a 3.0-l sample of oxygen was placed in an identical container. how many hours will it take for half of the oxygen to effuse through the membrane?

It will take 68.182 hours for half of the oxygen to effuse through the membrane

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or

the effusion rates of two gases = the square root of the inverse of their molar masses:

or

For 1.5 L O₂ it will take :

1.5 L : 0.022 L/Hr = 68.182 hours

inertia affect during a collision  

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Henry's Law  

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ideal gas  

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there are two significant figures.