What is the vapor pressure of a water solution at 25ºc containing glucose if the mole fraction of water is 2.0? the vapor pressure of pure water at 25ºc is 23.8 mm hg.

You must use Raoult's Law: the vapor pressure of a solution is equal to the vapor pressure of the pure solvent at the same temperature times the mole fraction of the pure solvent present: P = Xsolvent * Po

Po = 23.8 mmHg


Nevertheless there is an error in the statement because the mole fraction of any component is a solution cannot be greater than 1.  So, tha the mole fraction of water is 2.0 is wrong.

I will do it assuming that the mole fraction of water is 0.98


=> P = 0.98 * 23.8 mmHg = 23.3 mmHg

23.3 mmHg

The answer is b on plato.