How many milliliters of a 0.184 m lino3 solution contain 0.113 moles of lino3?

To determine the volume of LiNO3 present in 0.184 M LiNO3 solution, first note that the concentration of LiNO3 is expressed in units of molarity or moles per liter solution. Thus, given the molarity, 0.184 M, and the number of moles, 0.113 mol LiNO3, the volume of LiNO3 in milliliters can then be determined using this equation:

0.113 mol LiNO3/0.184 mol/L x 1000 mL/L = 614.13 mL LiNO3

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year