Chemistry, 18.07.2019 10:30, jesh0975556

What substance is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(l), and molten magnesium iodide, mgi2(l)? assume standard conditions. express your answer as a chemical formula?

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The substance that is produced at the cathode during the electrolysis of a mixture of molten calcium bromide, cabr2(I), and molten magnesium iodide, mgi2(I), can be expressed as Ca2+ + 2eâ’ --> Ca. At the anode, the substance can be expressed as 2Brâ’ â’ 2eâ’ --> Br2. At the cathode for magnesium iodide can be expressed as Mg2+ + 2 eâ’ --> Mg, and 2 Iâ’ â’ 2 eâ’ --> I2 at the anode.

answered: sofyan00404

The product deposited at the cathode of the electrolytic cell has been Bromine and Iodine.

Electrolysis has been defined as the decomposition of the chemical compound in the presence of the electric current.

The product of the chemical reaction has been deposited on the anode and cathode of the electrolytic cell.

Electrolysis of Calcium bromide and Magnesium Iodide

The anode in the cell has been the negative electrode and attracts the positive ions in the solution. The cathode has been the positive electrode, and attract negative ions.

The decomposition of calcium bromide results in the calcium and bromine ions, while magnesium iodide results in magnesium and iodide ions.

The product deposited at the cathode of the electrolytic cell has been Bromine and Iodine.

Learn more about electrolysis, here:
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answered: Guest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.