What mass of koh is needed to make 300.0 ml of 0.725 m koh? what mass of koh is needed to make 300.0 ml of 0.725 m koh? 86.4 g 30.5 g 23.3 g 12.2 g?

The given values in the problem are:

 .725 M is moles per liter 

300 mL = .300 L 

The solution is:

56.1 g/mol in 300 ml = 56.1g/mol in .3L 

M = (x gram/56.1) /.3L 

.725 = (x gram/56.1)/.3L 

Multiply both sides by .3

.2175 = x grams/56.1 

x = 12.20 g

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

a:

by the combination of an unlimited number of elements