If it takes three "breaths" to blow up a balloon to 1.2 l, and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 l balloon? express your answer to two decimal places and include the appropriate units.

0.45 moles of air are in a 3.0 l balloon

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.

The main composition of algebraic expressions are:

algebraic forms separated by arithmetic operations

consists of one phrase (monomial) to many phrases (polynomial)

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.

is a fixed value, can be a number

it takes three "breaths" to blow up a balloon to 1.2 l

we translate this sentence into Algebraic expressions:

3 breaths = 1.2 L

So for 3.0 l balloon will need:

3: 1.2 x 3 breaths = 7.5 breaths

Because each breath supplies the balloon with 0.060 moles of exhaled water, then for 3.0 L balloon there will be:

7.5 breaths x 0.060 = 0.45 moles

moles of water

link

grams of oxygen required

link

mass of copper required

link

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

→