Determine the [h3o+] of a 0.250 m solution of formic acid

Formic acid is a weak acid so it ionizes partailly and you need the ionization constant.

This constat is Ka = 1.77 * 10 ^ - 4

Now write the equilibrium reaction

HCOOH(aq) + H2O ⇄ H3O+(aq) + HCOO-(aq)

0.250M - x                       x                  x

Ka = [H3O+] * HCOO-] / [HCOOH]

1.77x10^-4 = x^2 / (0.250-x)

Solve for x and you get: x =

 x = 0.00656

[H3O+] = 0.00656 M

The independent variable is the type of music.the dependent variable is the pulse rate.the intervening variable is the age of the subject.if the mother does not like rock, her pulse is likely to not increase.the same might be true for the sister.the friend may like rap and gets excited.to establish cause/effect relationship, all of the subjects must be consistent.hope i .