Areagent bottle on the shelf labeled 0.5m nacl was used in place of the 0.5 m cacl2. assuming c2o4^2- to be in excess, what would be observed as a result of using this wrong reagent in this test? explain

Let's see the reaction for each situation.

2 NaCl + C₂O₄²⁻ → Na₂C₂O₄ + Cl₂

CaCl₂+ C₂O₄²⁻ → CaC₂O₄ + Cl₂

Thus, it would differ whether the main product is sodium oxalate or calcium oxalate. In their solid forms, both are white. However, calcium oxalate is insoluble in water, while sodium oxalate is slightly soluble. So, if you used NaCl instead of CaCl₂, you wouldn't observe any precipitate in your solution. If there is, it would only be minute.