What is the limiting reactant when 4.5 moles of aluminum react with 6.7 moles of oxygen gas? (4 points) unbalanced equation: al + o2 → al2o3

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The limiting reactant is Al.

Explanation: -

Number of moles of O₂ = 6.7 moles

The balanced chemical equation for this process is

4 Al + 3 O₂ → 2Al₂O₃

From the balanced reaction we see

3 mol of O₂ would react with 4 mol of Al

6.7 mol of O₂ would react with

= 8.933 mol of Al

But the number of moles of Al present is only 4.5 mol.

Hence the limiting reagent is Al.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.