Chemistry, 16.09.2019 13:30, Uhmjujiooo4220
Enough of a monoprotic acid is dissolved in water to produce a 0.0116 m solution. the ph of the resulting solution is 2.35. calculate the ka for the acid.
Answers: 1
= 1.72 × 10⁻³![K_{a} = \frac{[H_{3} O^{+}][ A^{-}] }{[HA]}](/tpl/images/0233/1446/cf7d2.png)
mol/L= 
mol/L = 4.47 × 10⁻³ mol/L
= 1.72 × 10⁻³
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