What is the mass in grams of 6.5×10^20 molecules of aspirin (c9h8o4) ?

The mass in grams of 6.5×10²⁰ molecules of aspirin (C₉H₈O₄) is 0.194 g

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of C₉H₈O₄

1 mole of C₉H₈O₄ = (12×9) + (1×8) + (16×3)

= 180 g

Therefore, we can say that:

6.02×10²³ molecules = 180 g of C₉H₈O₄

6.02×10²³ molecules = 180 g of C₉H₈O₄

Therefore,

6.5×10²⁰ molecules =

6.5×10²⁰ molecules = 0.194 g

Thus, the mass of 6.5×10²⁰ molecules of aspirin (C₉H₈O₄) is 0.194 g

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explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

the answer is minerals.