Suppose there are two known compounds containing the generic elements x and y. you have a 1.00-g sample of each compound. one sample contains 0.30 g of x and the other contains 0.39 g of x. identify plausible sets of formulas for these two compounds. xy and x3y x3y and x4y xy3 and xy4 x2y and x3y x4y2 and x3y x2y5 and x3y5 xy and x2y

To solve this, we must remember that the number of moles in each formula must a whole number.

So we are given two X’s:

X = 0.3

X = 0.39

We divide the two by the smallest X, so divide by 0.3:

X = 0.3 / 0.3 = 1

X = 0.39 / 0.3 = 1.3

However the second X is not a whole number yet, therefore multiply the two X’s by 3 to make them whole numbers:

X = 1 * 3 = 3

X = 1.3 * 3 = 4

So the X’s must be: X3 and X4 and based from the choices, the answer is:

X3Y and X4Y

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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