Calculate the number of carbon atoms in 25.0 grams of isopropyl alcohol (c3h8o)

There are 7.53×10²³ atoms of carbon in 25 g of isopropyl alcohol C₃H₈O

We'll begin by calculating the number of mole in 25 g of C₃H₈O. This can be obtained as follow:

Mass of C₃H₈O = 25 g

Molar mass of C₃H₈O = (12×3) + (8×1) + 12

= 36 + 8 + 16 = 60 g/mol

Mole = mass / molar mass

Mole of C₃H₈O = 25 / 60

Next, we shall determine the number of mole of C in 0.417 mole of C₃H₈O.

1 mole of C₃H₈O contains 3 moles of C.

Therefore, 0.417 mole of C₃H₈O. Will contain = 0.417 × 3 = 1.251 moles of C.

Finally, we shall determine the number of atoms in 1.251 moles of C. this can be obtained as follow:

From Avogadro's hypothesis,

1 mole of C = 6.02×10²³ atoms

Therefore,

1.251 moles of C = 1.251 × 6.02×10²³

Thus, we can conclude that 25.0 g of isopropyl alcohol, C₃H₈O contains 7.53×10²³ atoms of carbon.

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it is a solid

explanation: