Chemistry, 04.07.2019 22:40, naomicervero

You have 1 liter of a freshly prepared 0.1 m sucrose (molecular mass 342) solution, which means

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answered: yurionice42069

1 liter of 0.1 M sucrose solution means that there is 34.2 g of sucrose dissolved in water to make a 1 liter solution. This also means that there are 6.022 × 10²² molecules of sucrose in this solution.

FURTHER EXPLANATION

Molarity is a unit of concentration which describes the number of moles of solute dissolved per liter of a solution. It is calculated using the equation below:

$molarity = \frac{moles \ of \ solute}{volume \ of \ solution}$

Molarity is expressed with the unit mol/L or M (read as “molar”). It is a very useful unit of concentration because many quantitative information about the solution can be obtained from this value.

Mass of Solute from Molarity

From the molarity of a solution, the equivalent mass of the solute used to prepare the solution may be obtained with the use of the formula mass (or molecular mass) through the equation:

$molarity = \frac{\frac{mass\ of \ solute}{formula \ mass}}{volume \ of \ solution}\\\\mass \ of \ solute \ = molarity \times \ volume \ of \ solution \times formula \ mass$

Number of Representative Particles from Molarity

Moreover, the number of molecules of solute present in the solution may also be obtained using the molarity and Avogadro's number.

$molarity = \frac{moles \ of \ solute}{volume \ of \ solution}\\\\no. \ of \ representative \ particles \ = molarity \times volume \times 6.022 \times 10^{23} \ representative \ particles$

For this problem, the mass of the solute dissolved in the solution and the number of sucrose molecules may be obtained from the molarity of the solution.

Mass of Sucrose

$mass \ of \ sucrose \ = 0.1 \ \frac{mol}{L} \times 1 \ L \times \frac{342 \ g \ sucrose}{1 \ mol}\\\\\boxed {\boxed {mass \ of \ sucrose = 34.2 \ g \ sucrose}}$

Number of Sucrose Molecules

$no. \ of \ sucrose \ molecules \ = 0.1 \frac{mol}{L} \times 1 \ L \times \frac{6.022 \times 10^{23} \ sucrose \ molecules}{1 \ mol}\\\\\boxed {\boxed {no. \ of \ sucrose \ molecules \ = 6.022 \times 10^{22} \ molecules}}$

LEARN MOREWays of Expressing Concentration Empirical Formula

Keywords: molarity, molar concentration

answered: boyle3758

One litre of a freshly prepared 0.1 M sucrose solution means that 34.2 g of sucrose is dissolved in water to get final 1 L solution.

Further Explanation:

Concentration

It is a term that is used to relatedifferent components of solution with each other. A variety of concentration terms are employed to attain this. Some of the concentration terms are mentioned below.

1. Molarity (M)

2. Mole fraction (X)

3. Molality (m)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

7. Parts per billion (ppb)

Molarity is defined as moles of solute present in one litre of solution. It is represented by M and its unit is mol/L. The expression for molarity of solution is as follows:

${\text{Molarity of solution}} = \dfrac{{{\text{Moles }}\left( {{\text{mol}}} \right){\text{of solute}}}}{{{\text{Volume }}\left( {\text{L}} \right){\text{ of solution}}}}$

We are provided with 0.1 M sucrose solution. According to the definition of molarity, this indicates that 0.1 moles of sucrose are dissolved in 1 L of the solution.

The formula to calculate the moles of sucrose is as follows:

${\text{Moles of sucrose}} = \dfrac{{{\text{Mass of sucrose}}}}{{{\text{Molar mass of sucrose}}}}$ …… (1)

Rearrange equation (1) for mass of sucrose.

${\text{Mass of sucrose}} = \left( {{\text{Moles of sucrose}}} \right)\left( {{\text{Molar mass of sucrose}}} \right)$ …… (2)

Substitute 0.1 mol for moles of sucrose and 342 g/mol for molar mass of sucrose in equation (2).

$\begin{aligned}{\text{Mass of sucrose}} &= \left( {{\text{0}}{\text{.1 mol}}} \right)\left( {{\text{342 g/mol}}} \right) \\&= {\text{34}}{\text{.2 g}} \\\end{aligned}$

Therefore 34.2 g of sucrose is dissolved in water to get final 1 L solution.

Learn more:

Calculation of volume of gas: Determine how many moles of water produce:

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: concentration, concentration terms, solutions, molarity, molality, sucrose, moles, mass, molar mass, 342 g/mol, 34.2 g, 0.1 M, mass of sucrose.

answered: Guest

we need the questions , i may then you.

answered: Guest

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed