How many mol of cl are there in 385 grams of ccl4

Atomic mass of cl = 35.5 amu.

molar mass of ccl4 = (12) +4 (35.5)
= 12 + 142
= 154 amu.

mass of ccl4 = 385 g

no. of moles present = 385 / 154 = 2.5 mole
so, 2.5 mole of ccl4 is present in 385 grams .

The answer is 1.82 j/g°c                  

While unproven, it uses facts to support part of a conclusion. it is still factual and has predictive power, however.