How many bromine atoms are present in 33.8 g of ch2br2?

2.34 x 10^23 Calculate the molar mass of CH2Br2 Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight Bromine = 79.904 Molar mass of CH2Br2 = 12.0107 + 2 * 1.00794 + 2 * 79.904 = 173.83458 Now divide the given mass of CH2Br2 you have by the molar mass 33.8 g / 173.83458 g/mol = 0.194438 moles Since each molecule of CH2Br2 has 2 bromine atoms, multiply by 2 0.194438 * 2 = 0.388876 moles Finally, multiply by avogadro's number 0.388876 * 6.0221409 x 10^23 = 2.341866 x 10^23 Since you only have 3 significant figures, round the result to 3 significant figures. 2.341866 x 10^23 = 2.34 x 10^23

The independent variable is the type of music.the dependent variable is the pulse rate.the intervening variable is the age of the subject.if the mother does not like rock, her pulse is likely to not increase.the same might be true for the sister.the friend may like rap and gets excited.to establish cause/effect relationship, all of the subjects must be consistent.hope i .