Pls which volume of oxygen measured at room temperature and pressure is needed for complete combustion of 0.1 mol of propan-1-ol? a)10.8dm3 b)12.0dm3 c)21.6dm3 d)24.0dm3 answer is

The formula of this reaction is 2C3H7OH + 9O2 = 6CO2 + 8H2O. So there is 0.45 mol O2 for combustion of 0.1 mol 1-propanol. At STP, 0.45 mol has volume of 10.08 dm3. The room temperature usually is 20℃. According to the formula V1/T1=V2/T2, you can get the finally volume is 10.8 dm3.

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