Zinc mass if a 1.85 g mass of zinc produces 475 ml of gas and your balloon weighs 0.580 g and the room temperature is 21.5°c. calculate the amount of zinc needed to produce enough gas to get your balloon airborne by adding 1 ml to the required balloon volume so that its density is less than that of the surrounding air. (hint: complete balloon volume calculation as you did in question 2 above)

The weight of the balloon is irrelevant because it is the gas that lifts it in the air. We are already given with the required volume, so we use this instead. The atomic weight of zinc is 65.38 g/mol. Assuming ideal gas behavior,

PV=nRT
P(475 mL)(1 L/1000 mL) = (1.85/65.38)(0.0821 L·atm/mol·K)(21.5 + 273)
P = 1.44 atm

Then, we use this pressure and the volume to find the moles of zinc.

(1.44 atm)(475 mL+1 mL)(1 L/1000 mL) = n(0.0821 L·atm/mol·K)(21.5 + 273)
Solving for n,
n = 0.02836 moles of zinc

Ithink it’s 3 as the answer.

Matter- occupies space and possesses rest massno matter is the opposite