A thin strip of iron with a mass of 15.5 g is placed into a solution containing 21g of copper (ll) sulfate and copper begins to form. After some time, the reaction stops because all the copper (ll) sulfate has reacted. The iron strip is found to have the mass of 8.5g. The mass of copper formed is found to be 8.6g. What's the mass of iron (ll) sulfate which has been formed in the reaction?

Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]