Consider the reaction of glucose with oxygen: C6H12O6(s) + 6O2(g) Right arrow. 6CO2(g) + 6H2O(l) The enthalpy of formation (Delta. Hf) for C6H12O6(s) is –1,273.02 kJ/mol, Delta. Hf for CO2(g) is –393.5 kJ/mol, and
Delta. Hf for H2O(l) is –285.83 kJ/mol. What is Delta. Hf for O2(g)?

Given the following at 25c calculate delta hf for hcn (g) at 25c. 2nh3 (g) +3o2 (g) + 2ch4 (g) > 2hcn (g) + 6h2o (g) delta h rxn= -870.8 kj. delta hf=-80.3 kj/mol for nh3 (g), -74.6 kj/mol for ch4, and -241.8 kj/mol for h2o (g)

To calculate the molarity of a solution, you need to know the moles of solute and the

Astudent made the lewis dot diagram of a compound as shown. mg is written with two dots shown on its top. an o is written on each side of mg. each o has six dots around it. an arrow is shown from one dot on mg toward the vacant space around the o on the right. another arrow is shown from the other dot on mg toward the vacant space around the o on the left. the title of the art is students lewis dot model. what is the error in the lewis dot diagram? an o atom should transfer all its six electrons to mg because the formula is mgo. both electrons of mg should be transferred to one o atom because the formula is mgo. the electrons should be transferred from each o atom to mg because mg has fewer electrons. the number of dots around mg should be four because it has to transfer two electrons to each o.