Consider the following reversible reaction. Upper H subscript 2 upper O (g) double-headed arrow 2 upper H subscript 2 (g) plus upper O subscript 2 (g).

What is the equilibrium constant expression for the given system?
k subscript e q equals StartFraction StartBracket upper H subscript 2 upper O EndBracket over StartBracket upper H subscript 2 EndBracket StartBracket upper O subscript 2 EndBracket EndFraction.
k subscript e q equals StartFraction StartBracket upper H subscript 2 upper O EndBracket superscript 2 over StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper H subscript 2 EndBracket superscript 2 StartBracket upper O subscript 2 EndBracket over StartBracket upper H subscript 2 upper O EndBracket superscript 2 EndFraction.

a:

by the combination of an unlimited number of elements

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

the answer is a for sure mark brainliest i had got this right on usatestprep