Chemistry
Chemistry, 05.02.2022 01:20, rorathan123

Study the reaction. 2HCl (g)+I2 (s)β‡Œ2HI (g)+Cl2 (g)
When the reaction is at equilibrium, some amount of HI is added. The system then reaches equilibrium again.

How does the concentration of Cl2 change compared to the first equilibrium?

The concentration is higher.

The concentration is lower.

The concentration is zero.

The concentration is the same.

answer
Answers: 2

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Study the reaction. 2HCl (g)+I2 (s)β‡Œ2HI (g)+Cl2 (g)
When the reaction is at equilibrium, som...

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