How many liters of 3.0 M NaOH solution will react with 2.4 mol H2SO4? (Remember to balance the equation.) H2SO4 + NaOH → Na2SO4 + H2O 1.2 L 1.6 L 2.4 L 2.8 L

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol