In an experiment, 0.250 moles of propanoic acid, CH3CH2COOH were mixed with 0.150 moles of ethanol and the mixture was allowed to reach equilibrium. Given the total volume is 250 cm3 . CH3CH2COOH (aq) + C2H5OH (aq) ⇌ CH3CH2COOC2H5 (aq) + H2O (l) At equilibrium, 0.125 moles of propanoic acid remained. Calculate the value of Kc for the above reaction.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally