2 NOCl(g) → 2 NO(g) + Cl2(g) ΔH° = +75.56 kJ
2 NO(g) + O2(g) → 2 NO2(g) ΔH° = -113.05 kJ
2 N...
Chemistry, 05.12.2021 22:20, ZachLaVine2016
2 NOCl(g) → 2 NO(g) + Cl2(g) ΔH° = +75.56 kJ
2 NO(g) + O2(g) → 2 NO2(g) ΔH° = -113.05 kJ
2 NO2(g) → N2O4(g) ΔH° = -58.03 kJ
Compute ΔH° of N2O4(g) + Cl2(g) → 2 NOCl(g) + O2(g) in kJ.
Answers: 2
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