Chemistry
Chemistry, 03.12.2021 01:30, kingyogii

When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3, the more highly substituted alkene product predominates. When KOC(CH3)3 is used instead, the less highly substituted alkene product predominates. Offer an explanation.

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When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3, the more highly substituted alkene produc...

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