Using the equations H₂ (g) + F₂ (g) → 2 HF (g) ∆H° = -79.2 kJ/mol
C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol
2 C(s) + 2 H₂ (g) → C₂H₄ (g) ∆H° = -97.6 kJ/mol

Determine the molar enthalpy (in kJ/mol) for the reaction
C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g).

1.solid

2.carbon dioxide

3.helium

14 days is the half-life of phosphorus-32

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

it takes on an electronical energy