1. What is the specific heat of a substance that requires 270 J of energy to raise the temperature of 4.2 grams by 25°C?

Heat required is mcΔT=100×0.39×50=1950 J

Solve any question of Thermodynamics with:-

Explanation:

This will require  

266.9

k

J

of heat energy.

Explanation:

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material,  

m

The temperature change that occurs,  

Δ

T

Once you have all that, this is the equation:

Q

=

m

×

c

×

Δ

T

(

Q

is usually used to symbolize that heat required in a case like this.)

For water, the value of  

c

is  

4.186

J

g

°

C

So,  

Q

=

750

×

4.186

×

85

=

266

858

J

=

266.858

k

J

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.