Chemistry, 30.10.2021 21:30, cxttiemsp021

Phản ứng nhị hợp N02 2N02 ---> N2O4
biết ∆H (kcal/mol) : 8,091. 2,309
S. 57,2. 72,2
tính biến thiên năng lượng tự do của phản ứng ở 0°C và 100°C

Answers: 1

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Phản ứng nhị hợp N02 2N02 ---> N2O4
biết ∆H (kcal/mol) : 8,091. 2,309
S. 57,2. 72,2...