Cho 0,76 gam hỗn hợp hai amin no đơn chức có số mol bằng nhau tác dụng vừa đủ với 200 ml dung dịch HCl được 1,49 gam muối. Chọn mệnh đề
sai?
A. Nồng độ mol của dung dịch HCl bằng 0,1M.
B. Số mol của mỗi chất là 0,01 mol.
C. Công thức của hai amin là CH5N và C2H7N.
D. Tên gọi của hai amin là metylamin và etylamin.

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number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the answer is 0.8m.

by: nicholas