Nung 20 g CaCO3 và hấp thụ hoàn toàn khí CO2 sinh ra vào 0,5 lit dung dịch NaOH 0,56 M .Tính nồng độ mol của muối thu được

nCaCO3 = 20/100 = 0,2 mol

CaCO3 --> CaO + CO2

0,2 > 0,2

nNaOH = 0,5.0,56 = 0,28 mol

=> T = nNaOH/nCO2 = 0,28/0,2 = 1,4

=> sản phẩm tạo ra bao gồm : Na2CO3 và NaHCO3

NaOH + CO2 --> NaHCO3

x > x > x

2NaOH + CO2 --> Na2CO3 + H2O

y > 1/2y ---> 1/2y

ta có : nCO2 = nMuối = 0,2 mol

=> CmMuối = 0,2/0,5 = 0,4 M

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."