Calculate the osmolarity of a 1.15% (m/v) KBr solution.

1) Convert percent (m/V) to molarity

percent (m/V)=1.15 grams/100ml=1.15 g/0.1L=11.5g/L

molarity of KBr=mol/L=g/L *(1mol/molecular weight of KBr)=(11.5g/L) * (1mol/119.0g/mol)=0.0966 mol/L=0.0966M

2) calculation of osmol from mol

In solution, KBr dissociates into two ions K+ and Br- so there are 2 osmol of KBr per mol

3) calculation of osmolarity=molarity*2=0.0966*2=0.193 Osm or Osmolar

Explanation:

brainliest would be appreciated.

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.