If 43.0 grams of Sodium Carbonate reacts with 72.0 grams of Lead (IV) Chloride to yield Sodium Chloride and Lead (IV) Carbonate. (Write the equation, balance it and then solve the problem) A. How many grams of Lead (IV) Carbonate is produced
B. What is the limiting reagent
C. How many grams of the reagent in excess is left
D. If the % Yield is 54% then how many grams of Lead (IV) Carbonate is produced.

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.